## kwh to heat 1 litre of water

They are also measured by heat content. 1 kilowatt hour (kWh) = 3.6 megajoules 1 megawatt hour (MWh) = 3.6 gigajoules 1 kJ = 0.278 Wh 1 MJ = 0.278 kWh 1 GJ = 278 kWh 1 TJ = 278 MWh 1 PJ = 278 GWh 1 kWh = 3.60 MJ 1 calorie (c) = 4.19002 Joules Note 1 calorie is (approximately) the amount of heat required to raise the temperature of one ml of water by 1 degree Celsius. You used 0.001163 of one kilowatt-hour to heat your liter of water from 0°C to 1°C. Calculate the kilowatt-hours (kWh) required to heat the water using the following formula: Pt = (4.2 × L × T) ÷ 3600. Heating a full 184 litre (40g) tank costs $1.33 and $2.01 for a 279 litre (60g) tank. For 4 hours 488/4 = 122kw Water is heated to 90oC. A kilocalorie (C) is the amount of energy needed to heat 1 liter (1000 milliliters or 1000 cubic centimeters) of water one degree centigrade. One question which comes up time and again is “How many kW do I need to heat up my tank?”. The specific heat capacity of water is approx 4.2 J / g.K. 1) thermal transfer from heat source to water 2) As the water is heating up, the loss of water temperature due to conduction to the cooler surrounding air. -2°C to + 2°C) or from fluid to gas (e.g. Specific Heat Capacity: 4200 J / kg / C This is a measure of the amount of energy, measured in Joules, required to heat water. And as always, double check with some other source and my help is without any guarantee or similar. 1 litre of water is 1kg water-related energy use is at least 521 million MWh a year—equivalent to 13% of the nation’s electricity consumption. One kWh is 3413 Btu's, so one Btu is 0.000293 kWh. One Btu is 0.000293 kWh. It takes 667 92.7% = 720 Btu’s to heat a gallon of water using electricity. I'm looking for the same calculation, but for gas. This is the best set of calculators on the internet . 1kcal=1000cal. Last edited: Jun 16, 2016. heat of fusion of ice is 334 kJ/kg. One kWh is 3413 Btu’s. I’m curious, though. So it takes 525 ÷ 92.7% = 566 Btu's to heat a gallon of water in an electric tank. Change ), heating elements, immersion heaters, and more, Watt density and its importance for brewery immersion heaters. However this will require a much lower watt density than on a oil heater. This unit is less used than it was. To heat 1 ml of water takes 4.18 Joules per degree C, the specific heat capacity. specific heat of water is 4.186 kJ/kgC. All help is greatly appreciated - where possible, assume 'normal' conditions, i.e., use a standard or generally accepted density for air. C p is the specific heat of water (4.186 J/gm deg C) The calculator below can be used to determine the temperature delta or rise for a given cooling water application (heat load or power dissipated and cooling water flow rate) using the first formula above. It makes 1 out of 1.6, excellent piece of kit. Hi John, annual and total lifetime water heating costs based on different water heating systems and energy sources. The following formula is used to calculate the power of heating element needed to heat a specific volume of water by a given temperature rise in 1 hour. ( Log Out / 250 us gallons at 105f with moderate insulation… would 100 watts DC heater maintain this temperature? … With a 3 hour design reheat time, this means a power input of about 2600 watts. This is great. I am guessing its q=m*cp*dt but when I do the calcs by hand, i get something off so i would like to know my mistake, How much heat energy in joules is necessary to raise the temperature Of 7000 kg (7 M3) of water from 20 °C to 80 °C? At $1.20 /therm, it costs 11.31 x $1.20 = $13.58 to heat 1000 gallons. The cost of electricity is for example 7.15 €ct per kWh and for natural gas is 28 €ct per m 3 of gas. Now, 1 kWh contains 3.6 MJ/kWh. The gas needed depends on your boiler, it's perhaps 60% efficient. volume in litres x 4 x temperature rise in degrees centigrade / 3412, (4 being a factor and 3412 being a given constant), for example 100 litres of water, to be heated from 20ºC to 50ºC, giving a temperature rise of 30ºC would give –. specific heat of steam is 2.1 kJ/kgK. Calculation for working out factor to convert litres of heating oil into kWh / litre. How much heat energy in joules is necessary to raise the temperature Of 7000 kg (7 M3) of water from 20 °C to 80 °C? This means that you will have to pay 23 €ct to heat the bathwater with electricity and and 12 €ct to heath with gas if you take a bath (exlusive watercosts). Thanks! Running a bath will use approximately 60 - 80 litres of water. A typical electric water heater is 90.4 to 95% efficient. 1 Watt = 1 Joule of energy per second 1 kW = 1000 Joules of energy per second. EDIT: My gas is billed in 15kg gas cylinders, but feel free to allow for liters of gas. The insulation of where the heating device sits and whether any heat can escape into something other than the water (like a wall, concrete etc.) Also we can use this formula as the basis of similar calculations for heating oil. The immersion stat will control temperature which will normally be well under boiling point - so 65 degrees or so, depending on what it is set at. I'm heating a liter of water from 25C to 60C. Over an hour it would be “kWh”. 1 Watt = 1 Joule of energy per second 1 kW = 1000 Joules of energy per second. One kilo calorie is the amount of heat needed to raise the temp. To determine BTU lost can I use the “Water Heating Energy Calculator” only backwards? Since water gets lighter when heated it will start to ascend around the coil and cold water will flow to the coil from below. If you use a 611 watts heater in this example, then it will be about enough to reverse this cool-down from 105f to 103f by heating the water back up from 103f to 105f during the same period (realistically, of course, the water does not cool down, but stays at the same temperature). Using the “Water Heating Power Calculator” above (250 us gallons, start temperature 103f, end temperature 105f, 120min) tells us that a heating power of 611 watts is required. There are many other factors including the temperature of the cold water entering the heater system, the temperature of the hot water coming out of the heater and hot taps and the cost per kWh of the energy. Nice calculator buttt…… you’ve got the abbreviations for the metric units incorrect. Great calculator. I am looking for how much energy is need to maintain water temperature. 180 litres of water is near enough 180kg. If using electric it's near enough 100% energy conversion from energy paid for to heat, but leccie is more expensive than gas per kWh (see bills). Also, the calculator is only correct in the theoretical case that while the water is being heated, no heat escapes from the water to the environment (air or walls etc.). At $0.30/kWh that's $2.85. how to calculate power required to heat water. This calculator tells how much energy will be consumed to heat the water from the start to end temperature. E = (4.2 kJ/kgoC) ( (90 oC) - (20 oC)) (1000 liter) (1 kg/liter) = 294000 kJ. A 60 watt light bulb uses 60 watt-hours of energy in one hour. Your immersion could be slightly faulty, or be covered with scale in some hard water areas . I'm looking for the same calculation, but for gas. I just recently learned about hybrid heat pump water heaters for the home that have much higher heating efficiency than standard electric. I have done the calculations in the calculator above for heating 33’000 US gallons from 68F to 90F in 5h (300min) and got a result of approximately 1’200’000 btuh. The higher element usually is for when you need to heat some water in middle of day. ΔT = 80-20 = 60 C Hi all. Is that realistic? To boil ALL the water: Density: 1000 kg / m 3 or 1 kg / litre This is a measure of the mass (weight) of a set volume of water. Also we can use this information to extrapolate both ways. I entered 688 litres start temperature 29 C end temp 37 C with 1600 watts of power. Create a free website or blog at WordPress.com. There are many other factors including the temperature of the cold water entering the heater system, the temperature of the hot water coming out of the heater and hot taps and the cost per kWh of the energy. 1 to heath one liter of water … For Heating Water in Tanks: KW = Liters x Temperature Rise (°C) 790 x Heat-up Time (hrs.) There's a great answer about heating water with electricity, where anyone can easily get an idea how much would it cost to heat water just by applying one's price for kWh. Often, energy is measured in kWhs There's a great answer about heating water with electricity, where anyone can easily get an idea how much would it cost to heat water just by applying one's price for kWh. that is impossible to calculate with the information given. Gas Engineer. The answer is 6 hours 24 minutes. ( Log Out / Calculation for working out factor to convert litres of heating oil into kWh / litre. I am wondering though, doesn’t heat capacity increase with temperature, potentially throwing off the calculation? The power in watts is then found by: energy (joules) / time (seconds) To convert that answer to kilowatts, divide by 1000. L is the number of liters of water that is being heated and T is the difference in temperature from what you started with, listed in degrees Celsius. That’s just an example, I have no idea how fast a tub cools down. The amount of energy needed to raise the temperature of 1 g of water by 1 degree Celcius or (1 Kelvin) equals 1 calorie. of 1g water by 1˚C . Your calculators are a big help in figuring the size of the heat sump. This calculator is great. How do I calculate btu size for heating a swimming pool? So they may complain when you input commas or points. at 1:57 PM. Problems with limit calculations: It complains if the end temp is 212°F or even 211°F, saying it must be less than boiling. One gallon of gasoline (petrol) is about 118,000 BTU. I'm under the impression that a Calorie (kcal) heats one liter of water by one degree, and so heating one liter by 35 degrees requires 35 Calories. I have done the calculation again manually in an Excel spreadsheet and got the same result. Where C p is the heat capacity of water (1 BTU/lb/F) and m is the mass of the water (Assume 1 gal has 8.3 lb of water and the 3,412 BTU = 1 kWh) Solution: Energy required for heating the water to 120°F: = m × C p × ΔT = 100 gal day × 8.3 lb gal ︸ m × 1 BTU lb °F ︸ C p × (120 − 65) °F ︸ ΔT = 100 gal day × 8.3 lb gal × 1 … 1 litre of water has a mass of 1 kg. Specific Heat Capacity: 4200 J / kg / C This is a measure of the amount of energy, measured in Joules, required to heat water. Great help to calculate water flow and energy consumption! According to "latent heat of vaporization of water" it would take around 0.62 kWh/liter but I'm not sure...please help! There are others who need guidance and advice as to what they need. 1 litre of water is 1kg 1 meter cube = 1000 Ltrs M = 7 meter cube = 7000 Ltrs or 7000 Kg The heat capacity Cp of water is 4.186kJ/kg-C ΔT = 80-20 = 60 C Heat capacity formula. Here’s a breakdown of how hot water is used in an average month. So 78 C rise requires 326,508 Joules per kg. This was super helpful in calculating the power needed to produce my hot water via solar photovoltaics. for example 100 litres of water, to be heated from 20 ºC to 50 ºC, giving a temperature rise of 30 ºC would give – 100 x 4 x 30 / 3412 = 3.52 meaning that the water would be heated in 1 hour by 3.5kW of applied heat. Only input whole numbers, do not use a comma or point. It takes 667 92.7% = 720 Btu’s to heat a gallon of water using electricity. The calculators support Celcius/Centigrade, Fahrenheit, Watts (w), Kilowatts (Kw), Btuh, Joule, British termal unit (Btu), liter, gallon, kg, lb, cubic inch, cubic foot etc. The calculators on this page compute how long it takes to heat water, how much energy is consumed, and how much heating power is required. is more important for efficiency. 100 kcal of heat is required to raise the temp of 1 kg water from 0 ˚C to 100 ˚C. meaning that the water would be heated in 1 hour by 3.5kW of applied heat. K). Thats $0.01275 per gallon for gas and $0.01825 per gallon with electric. Improved calculators that support comma, dot, and efficiency, are available here: time, energy, and power. So one Btu is 0.00001 therms. The calculators cannot handle points or commans, only whole numbers. Also we can use this information to extrapolate both ways. For 8 hours 488/8 = 61kw. 1 BTU is the amount of heat required to raise the temperature of 1 pound of water 1 degree F. (1 kg x 1 degree C would be 3.96 BTU.) @Anna This is why the calculators complain in these situations. I’ve been looking for a simple way to ballpark the size of a solar thermal hot water system – and this makes it dead simple! Thank you! Heating water to have a bath can be a major cost on your energy bills depending on how you heat the water and how much water you use. This way a circulation develops in the water container given the shape of the water container permits it. 1 L water = 0.998 kg. Water at room temperature 22 C must be raised to 100 C and heat of vaporisation added to become a gas. ie, the metal kettle on the gas hob, would loose more water temperature, than say the plastic, electric kettle, as plastic is a better heat retainer than metal. If i change the power to 1.6kw . Boil or evaporate? The increase in temperature is 45 Kelvin (60-15) So the energy needed is 180,000 x 45 x 4.2 = 34MJ. To heat the same water volume in half the time (30 minutes) would need twice the heating power, ie, 7kW. If we can calculate the volume of water and the required temperaure rise, we can answer this question. Pt is the power used to heat the water, in kWh. of 1kg water by 1˚C . Let's call that 92.7% on average. (U.C. I’m looking at a 50,000 btu boiler with a heat exchanger to heat a 33,000 gallon pool to 90 degrees f. I’ve run then calculation through the formula above, and it’s coming up with a 600,000 btu boiler to raise the water temp (68f) in 5 hours to 90f, which seems to be a really high number? That is a 1 ATM. The heat capacity Cp of water is 4.186kJ/kg-C Cost To Heat Water Using Electricity A typical electric water heater is 90.4 to 95% efficient or 92.7% average efficiency. Hot water immersion heater elements are usually rated at 3 or 6 Kilowatts (kW). For Heating Water in Tanks: KW = Liters x Temperature Rise (°C) 790 x Heat-up Time (hrs.) I want to convert this to Watthours but I'm not sure how....does bringing time into the equation determine how much energy I need to expend? Sweet! 1kWh = 1000W x 3600s = 3.6MJ. As 1 litre of water needs about 1.16 watts to raise it through 1°C in an hour, a 120 litre tank of cold mains water needs a total energy input of about 7800 watts-hours (120*1.16*56) to raise its temperature to the required level. meaning that the water would be heated in 1 hour by 3.5kW of applied heat. At Process Heating Services, we have 2 types of customer. Formula to calculate electricity or gas consumption of water heating . How much depends on the shape of your pool, the quality of the insulation of the pool, the difference of the desired water temperature to the environment and how long you are willing to wait until it is heated. Often, energy is measured in kWhs Thermal radiation losses occur from direct sunlight, high water temperature or high relative humidity. Roughly speaking, due to its density and viscosity, heavy oil will heat up in half the time of water, or if you prefer, require around half the heating power to heat up the same volume of water in the same period of time. Example - Batch Heating with Steam . it takes the same amount of energy to heat water from 48 degrees to 52 degrees as it takes to heat water from 58 degrees to 62. I have saved the page to my home screen. For rocket science one might want to calcualte it more accurately. Density: 1000 kg / m 3 or 1 kg / litre This is a measure of the mass (weight) of a set volume of water. At $0.11/kWh, it costs 6.63 x $0.11 = $0.73 to heat a 40-gallon tank." Heating oil provides 138,500 British thermal units (BTU) per US gallon; 1 BTU = 0.000293 kWh; 1 US gallon = 3.78541178 litres (138,500 * 0.000293)kWh in 3.78541178 litres (138,500 * 0.000293)/3.78541178 kWh/litre = 10.720233982047786621512547837002 As for effectiveness, a large enough pipe with a pump can probably in theory transfer more heat per second (meaning power, e.g. density of water is 1g/cu.cm or 1kg/cu.d. One therm is 100,000 btu's. I'm under the impression that a Calorie (kcal) heats one liter of water by one degree, and so heating one liter by 35 degrees requires 35 Calories. So, this is 12.8889 kWh/liter of heat energy. It complains when volume is 0.25 US gallon, saying volume must be greater than zero. Energy E = m•Cp•ΔT = 7000 x 4.186 x 60 = 1758120 kJ Save my name, email, and website in this browser for the next time I comment. I know that "both heat of vaporization plus the heat required to raise the water to 100°C" but the energy required to raise the water to 100°C contributes just 5% of the total requirement . This is for a hot tub, I do not need to increase or decrease the temperature. Hot water cylinders/tanks come in many shapes, sizes and capacities, ranging from 40 to over 400+ litres in larger homes. When using a simple coil submerged in water, then it will start to heat the water just around it. With a 3 hour design reheat time, this means a power input of about 2600 watts. We normally see energy in our electricity meter and bill as kilo-watt hours, rather than kilo-joules, so we have to divide by 3,600 (the number of seconds in an hour) to convert them — so 18,900 KiloJoules is 5.25 kilowatt-hours (18900 ÷ 3600 = 5.25) So basically I use 5.25 electricity credits every day heating up water. If you can test how fast the water cools down in your tub, then you can calculate how much heating power is required to prevent that from happening. Cost To Heat Water Using Electricity A typical electric water heater is 90.4 to 95% efficient or 92.7% average efficiency. Hence, the energy needed is 34/3.6 = 9.5 kWh. The volume in gallons (5), ambient temperature (46F) and target temperature (161) are variables that will change. One kWh is 3413 Btu's, so one Btu is 1/3413 = 0.000293 kWh. The energy stored in the water tank can be calculated as. natural gas, or kilowatt hours or electricity (kWh). Click HERE for our online water heat up time calculation page. Let’s make a calculation example for a tub with 250 us gallons that cools down from 105f to 103f in 2 hours. watts) to water. Think of power as the rate at which energy is used. The cost of electricity is for example 7.15 €ct per kWh and for natural gas is 28 €ct per m 3 of gas. Change ), You are commenting using your Facebook account. The two keys they had were that it cost $0.51 to heat 40 gallons using gas or $0.73 using electric. As such, for every litre of hot water, you need to factor in: the price of a litre of water; the write-off of the purchase price and the installation cost of your domestic hot water generating system; your energy consumption to heat this litre of water. It would be more complicated to build calculators that can handle that and I have not done so. But I have an idea. It would be really cool to see a calculator that takes this new technology into account. 566 Btu's x 0.000293 kWh/Btu = 0.166 kWh. May 21, 2010 #4 PaulS1950. I just want to maintain the temperature. Under partial vacuum, such energy requierement can be less. The immersion stat will control temperature which will normally be well under boiling point - so 65 degrees or so, depending on what it is set at. It depends how much you want to heat the water up by: As a general rule, the energy (in joules) to heat water is given by: Energy = mass of water (kg) x temperature rise (celsius) x 4200. 3412 BTU = 1 kWh. Cost of 1 litre of hot water according to appliance type . A litre of water at 25℃ needs a certain amount of calories to become steam at 100℃ ∆t=75℃ (75Kcal + 540Kcal =615Kcal) if I remember the figures. As for efficiency, an electrical water heater can convert electricity with almost 100% efficiency to heat that can be transferred to the water. And for testing/sampling the cool-down, measure a larger drop in temperature, such as 10f, else the result will be unreliable (reading 1f or 2f changes off a small thermometer may be very inaccurate). specific heat of ice is 2.06 kJ/kgC. Hi “New pool, cold water !” Thermal radiation losses are responsible for 20%-30% of heat energy loss in the swimming pool. Thus,mass of 1l water=1kg. So we've got 0.166 kWh to heat a gallon of water, or 0.166 x 40 = 6.63 kWh to heat a 40-gallon tank. is this calculation valid only when submerging the heating device in the water, or also when the water is circulating through a heating pipe using a pump? Hi Larry, the energy that is used to heat water from 40 degrees to 60 is the same amount that is lost when the water cools down from 60 to 40 (only changed sign). One Btu is 0.000293 kWh. It takes about 1/10 kWh of energy to boil a litre of water and around 5kWh to heat a bath. But when the state of water changes from solid to fluid (e.g. I’m trying to figure out what would it take to heat my pool using a heating pipe after the filtration pump. For an electrical heater that can be a good assumption, but not for a gas heater. Specific heat capacity of water kcal/kgx°C 3: 1. I do not think it makes much of a difference in practice. That means that for every 10 litres of hot water you use will only cost you 7 cents. This means that you will have to pay 23 €ct to heat the bathwater with electricity and and 12 €ct to heath with gas if you take a bath (exlusive watercosts). What formula did you use to calculate the water heating power? The heat capacity is largely constant in the temperature range that the calculators work (34-210°F or 1-99°C). A BTU is the amount of energy required to heat 1 pound of water by 1°F (specifically from 39° to 40°F). If you have problems with the units, feel free to use our temperature conversion or weight conversion calculators. It also should be noted that the difference between the starting temperature and the desired final application temperature is commonly referred to as delta T (ΔT). Also, you should have some extra power available, just to be sure. Heating oil provides 138,500 British thermal units (BTU) per US gallon; 1 BTU = 0.000293 kWh; 1 US gallon = 3.78541178 litres (138,500 * 0.000293)kWh in 3.78541178 litres (138,500 * 0.000293)/3.78541178 kWh/litre = 10.720233982047786621512547837002 Running a bath will use approximately 60 - 80 litres of water. Lecci is about 10p / kWh, so about 50p for a bath and 10p for a litre of tea. , As another calculator for us math dummies could be total kw x cost of electrical supply. 98°C to 102°C) this does not hold true any more. However, oil needs a much lower watts density element than water, as described in the “How to choose an oil heater” article. 1 to heath one liter of water it will cost one kcal, what equals 4.18 kJ. If you want to boil it and turn it all completely into steam, you'll need another 0.7421 kilowatt-hour As 1 litre of water needs about 1.16 watts to raise it through 1°C in an hour, a 120 litre tank of cold mains water needs a total energy input of about 7800 watts-hours (120*1.16*56) to raise its temperature to the required level. I'm heating a liter of water from 25C to 60C. 1 meter cube = 1000 Ltrs Irvine) Heating a gallon of water by 1°F with no losses thus takes 8.33 ÷ 100,000 = 0.00008.33 therms. This calculator tells you how long it takes to heat water from start to end temperature with a given heating power. Hot water immersion heater elements are usually rated at 3 or 6 Kilowatts (kW). This is the typical heat capacity of water. Time period available to heat the water (minutes), Water Heating Calculator for Time, Energy, and Power. heat of vaporization of water is 2256 kJ/kg. Posted on March 13th, 2016 How long would it take a kettle with a 1kW heating element to heat 1 litre of water? And 1 calorie equals 4,184 Joule. Hot water cylinders/tanks come in many shapes, sizes and capacities, ranging from 40 to over 400+ litres in larger homes. There are those who tell us what they want as they know their exact requirements. I am tasked to maintain a 110L aquarium at 22-24C outdoors in Texas. ( Log Out / Water Litre to kg: 1 Litre = 0.999975 kg, so for all practical purposes 1 L = 1 kg Water kg to Litre: 1 kg = 1 litre Example: LPG Gas 14.2 kg Equals How Many Liters with 75% Butane For LPG (propane) 1 kg = 1.96 L. Therefore, 14.2 kg = 27.832 L. For LPG (butane) 1 kg = 1.724 L. Therefore, 14.2 kg = 24.48 L This calulator tells you how much minimum heating power is required to heat the water within a specified amount of time. For that reason, these values are the minimum and some margin should be added to them. The calculators use the specific heat capacity of water of 4186 J/kg/°C (Joules per kilogram per degree Celsius). The higher element usually is for when you need to heat some water in middle of day. So if you want to raise the temperature of 1 litre of water (1 litre = 1000g for water) by 80 degrees Celcius, your calculation should look like this: 1000g*4,184J/ (g*°C)*80°C= 334 720 Joules 1 kWh = 3 600 000 Joules, because 1 watt of power during 1 second equals 1 Joule. Start temp as final and end temp as start. For practical purposes, it should be precise enough. 488 kwh for 1 hour I think of it this way: the power limit of heating coil simply submerged in water is reached when the water starts to boil around the coil while the water in other places is still much colder. Converesely, if we only use half the heating power, 1.75kW, it will take twice as long to heat up to desired temperature, ie, 2 hours. Generally, oil heats up in half the time of water, due to its density. I am assuming calculations take into account the specific heat capacity of water? Our updated website is up, running and ready for viewing. Thank you. To heat the same water volume in half the time (30 minutes) would need twice the heating power, ie, 7kW. = (294000 kWs) (1/3600 h/s) = 81.7 kWh. Specific heat capacity of water kcal/kgx°C 3: 1. Straight to the point. A Watt is named after James Watt hence the abbreviation is a capital W. A thousand of something is a “kilo” for example a kilogram. The calculators assume 100% efficiency and no loss of energy during the heating process. While this appears to be a conservative estimate of water-related energy use, our findings suggest that the carbon footprint currently associated with moving, treating and heating water in the U.S. is at least 290 million If we only have a 1kW element available, we will expect a heat up time in excess of 3 hours. 1 C. colshaws. 1 litre for 1 degree in 1hour is 1,16 kW/h. To heat the water to boiling: E = 4.186 kJ/kgC x 0.998 kg x 76C = 317.5 kJ = 0.088 kW-hr. Heating a gallon of water by 1°F with no losses thus takes 8.33 lbs x 1 Btu/lb = 8.33 Btu's. Change ), You are commenting using your Google account. Solve for Thermal Power Thanks!!! Last updated on April 16th, 2020. is there a formula to calculate the temperature required for 5 gallons of water that will increase the temperature of a stainless steel 15.5 gallon tank from 46F to 161F. An I missing something here? Hi, I am trying to calculate the energy required to heat air that is 6.7 degrees C to 21 degrees C, in kilowatt hours, and for a range of other temperatures (5.7, 6.9, 9.5..... and many others, all to 21 degrees celsius/centigrade). They are saying the modern heat pumps can give you 3.8 watts worth of hot water (or something close to that) for each watt that the heat pump uses. Volume of fluid to heat in litres: Starting temperature degrees C: Target temperature (finishing) degrees C: Heating power kW: Density of water kg/dm 3: 1. time required to reach target temperature at given power: hours or = 488 .36 KW Power = Energy / time Please remember, that the calculators above assume 100% conversion efficiency. 1758120 kilojoule/hour = 488.36666667 kilowatt hour One calorie is the amount of heat needed to raise the temp. Fill in your details below or click an icon to log in: You are commenting using your WordPress.com account. 1000 watts is 1000 Joules per second, but spread over 1000 ml. This is the typical heat capacity of water. • The heat content of one gallon of fuel oil roughly equals that of 41 kWh of electricity, 137 cubic feet of natural gas, 1.5 gallons of propane, 17.5 pounds of air-dried wood, 17 pounds of pellets, a gallon of kerosene, or 10 pounds of coal. In the United States, the most commonly used value for expressing the energy value or heat content of a fuel is the British thermal unit (Btu). In turn the abbreviation, for one thousand, is k. Bringing these two together, a kilowatt is a “kW”, not as you have, “Kw”. This is also The value of the specefic heat of water. If you have problems with the units, feel free to use our temperature conversion or weight conversion calculators. So, the energy required to raise the temperature of 7000 kg of water from 20C to 80C is: For less than the price of a new heater tank, I now have free hot water. Wouldn’t it be faster in the latter case, because the water flow would exchange heat more efficiently than just by convection? Heating water to have a bath can be a major cost on your energy bills depending on how you heat the water and how much water you use. This kind of thermal radiation is similar to feeling the heat of a campfire on your face from a distance. Energy rates as of November 1, 2020. Also we can use this information to extrapolate both ways. Appreciate the calculators but i was wondering if you could tell me the exact equations used for the “Water Heating Energy Calculator” or give some sort of excel sheet to double check it. The surrounding temperature (where the energy can be transferred to) is 20oC. One kWh is 3413 Btu’s. It very much depends on the surrounding temperature, the heat conductivity of your hot tub material, and the shape of the tub. At $1.20 /therm, it costs 11.31 x $1.20 = $13.58 to heat 1000 gallons.

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